Question 42859
From
6^(n+1) ≥ 10
take the log of both sides, apply the power rule and solve for n...we get
log 6^(n+1) ≥ log 10
log 6^(n+1) ≥ 1
(n+1)*log 6 ≥ 1
n + 1 ≥ 1/log 6
n ≥ (1/log 6) - 1
n ≥ .2851