Question 393211
{{{f(0) = 2}}}
{{{f(x + 1) = 3*(f(x) - 5)}}}
I can say that {{{x = 0}}} and {{{f(x) = 2}}}
{{{f(1) = 3*(2 - 5)}}}
{{{f(1) = -9}}}
Now I'll say {{{x = 1}}}, {{{f(x) = -9}}}
{{{f(2) = 3*(-9 -5)}}}
{{{f(2) = -42}}}
Set {{{x = 2}}} , {{{f(x) = -42}}}
{{{f(3) = 3*(-42 - 5)}}}
{{{f(3) = -141}}}
Set {{{x = 3}}}, {{{f(x) = -141}}}
{{{f(4) = 3*(-141 - 5)}}}
{{{f(4) = -438}}}