Question 393193
  <pre><font size = 3 color = "indigo"><b>
Hi
Solve for x 
log x +log(x-5)=log14
log x(x-5)/14 = 0
 10^0 = x(x-5)/14
  1 = x(x-5)/14
  14 = x(x-5)
 x^2 - 5x - 14 = 0
factoring
 (x+2)(x-7)=0 Note:SUM of the inner product(2x) and the outer product(-7x) = -5x
 (x+2)= 0  negative solution is extraneous 
 (x-7)=0 
    x = 7