Question 393180

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Hi
Note: The probability of x successes in n trials is: 
P = nCx* {{{p^x*q^(n-x)}}} where p and q are the probabilities of success and failure respectively. In this case p =.17 q = .83
nCx = {{{n!/(x!(n-x!))}}}
P(exactly 4 hits out of 7 at bat) = 35(.17)^4(.83)^3 = .0167

Coin experiment p and q = 1/2 or .5
P(3 heads out of 10 flips) = .1172 =  120*(.5)^3(.5)^7
P(at least 3 heads out of 10 flips) = .9453 = 1-P(0)-P(1)-P(2)