Question 393166
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Hi
Note: The probability of x successes in n trials is: 
P = nCx* {{{p^x*q^(n-x)}}} where p and q are the probabilities of success and failure respectively. 
In this case let p(defective) = 4/30 = 2/15 & q = 7/15
nCx = {{{n!/(x!(n-x!))}}}
P(3 chosen are all defective) = (2/15)^3 = .0024