Question 392998
{{{x^2*(1/9x^3)*(63x^(-11))}}}
First we will simplify the expression. Then we will put it in the {{{c/x^e}}} form.<br>
To multiply we will start by making everything a fraction:
{{{(x^2/1)*(1/9x^3)*(63x^(-11)/1)}}}
When we multiply the numerators we will use the rule for exponents when we multiply the x's: Add the exponents:
{{{(63x^(2+(-11)))/(9x^3)}}}
which simplifies to:
{{{(63x^(-9))/(9x^3)}}}
63/9 = 7 and to divide the x's we use the rule for exponents when you divde: Subtract the exponents:
{{{7*x^(-9-3)}}}
or
{{{7*x^(-12)}}}
The expression is now simplified. To put it in {{{c/x^e}}} form we will use a property of negative exponents: {{{a^(-q) = 1/a^q}}}
{{{7*(1/x^12)}}}
which simplifies to
{{{7/x^12}}}
We can now see that c = 7 and e = 12.