Question 393063
f(x)=3/x+2 + x-4/x+3
=(3(x+3)+(x+2)(x-4))/(x+2)(x+3)
x cannot be -2 or -3 because there would be division by zero in the denominator.
X(-infinity, -3)U(-2, infinity)
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Ed
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{{{graph(500,500,-10,10,-100,100,(3/(x+2)) + ((x-4)/(x+3)))}}}