Question 42835
Let length be x. So the width is x-1.


A Rectangle...quoted the diagonal. Draw this and you see a right angled triangle...Pythagoras' Theorem.


Hence: {{{ x^2 + (x-1)^2 = 4^2 }}}
{{{ x^2 + x^2 - 2x + 1 = 16 }}}
{{{ 2x^2 - 2x - 15 = 0 }}}


Solve this quadratic... either factorise or use the quadratic formula.


Good luck
jon.