Question 392700
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Hi
Note: 'log' is base 10 and 'ln' is base e, (assume by log2..You mean base 2)
Applying properties of logarithms
1. *[tex \LARGE \ \  4*log(x)\ = 5 \ \Rightarrow\ \ log x^4 = 5 \ \Rightarrow\ \ 10^5 = x^4] 
2. log2 x + log2 4 = 3
*[tex \LARGE \ \  log_2(x/4)\ = 3 \ \Rightarrow\ \ \ \ 2^3 = x/4] 
3. ln 3x = 6 *[tex \LARGE \ \Rightarrow\ \ ] e^6 = 3x
4. ln x + ln 1 = 5  *[tex \LARGE \ \Rightarrow\ \ ] e^5  = x*1
5. ln x + ln (2x-1) = 0 *[tex \LARGE \ \Rightarrow\ \ ] e^0 = x(2x-1)
will leave the calculator work up to You