Question 392655
Solve for x algebraically.
Square root of (x+1) + Square root of 2x=Square root of 5x+3
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{{{sqrt(x+1) + sqrt(2x) = sqrt(5x+3)}}}
Square both sides
{{{x+1 + 2x + 2sqrt(2x(x+1)) = 5x+3}}}
{{{2sqrt(2x^2+2x) = 2x +2}}}
Square again
{{{4(2x^2+2x) = 4x^2 + 8x + 4}}}
{{{8x^2 + 8x = 4x^2 + 8x + 4}}}
{{{4x^2 - 4 = 0}}}
x = ± 1