Question 392588
8b^(2)+24b+18

Factor out the GCF of 2 from each term in the polynomial.
2(4b^(2))+2(12b)+2(9)

Factor out the GCF of 2 from 8b^(2)+24b+18.
2(4b^(2)+12b+9)

In this problem (3)/(2)*(3)/(2)=9 and (3)/(2)+(3)/(2)=12, so insert (3)/(2) as the right hand term of one factor and (3)/(2) as the right-hand term of the other factor.
2(b+(3)/(2))(b+(3)/(2))

Remove the fraction by multiplying the first term of the factor by the denominator of the second term.
2(2b+3)(2b+3)

Combine the two common factors of (2b+3) by adding the exponents.
2(2b+3)^(2)