Question 42784
Hi! You already know that, in a right triangle, {{{a^2 + b^2 = c^2}}}. We know that b = 10 (it could be a as well), so b^2 must equal 100. But that's still not using the whole information of the problem. We know that c = a+2, or a = c-2. Let's try and substitute for a:

{{{a^2 + 100 = (a+2)^2}}}

Expanding the right part (a*a + a*2 + 2*a + 2*2) gives 

{{{a^2 + 100 = a^2 + 4a + 4}}}

Subtracting a^2 from each side, you get a first degree equation, which should be easy! 

{{{100 = 4a + 4}}}

If 96 = 4a, a = 24 and a+2 = 26.