Question 392551
x+y=35_x=4y

Since y does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting y from both sides.
x=-y+35_x=4y

Replace all occurrences of x with the solution found by solving the last equation for x.  In this case, the value substituted is -y+35.
x=-y+35_(-y+35)=4y

Remove the parentheses around the expression -y+35.
x=-y+35_-y+35=4y

Since 4y contains the variable to solve for, move it to the left-hand side of the equation by subtracting 4y from both sides.
x=-y+35_-y+35-4y=0

Since -y and -4y are like terms, subtract 4y from -y to get -5y.
x=-y+35_-5y+35=0

Since 35 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 35 from both sides.
x=-y+35_-5y=-35

Divide each term in the equation by -5.
x=-y+35_-(5y)/(-5)=-(35)/(-5)

Simplify the left-hand side of the equation by canceling the common factors.
x=-y+35_y=-(35)/(-5)

Simplify the right-hand side of the equation by simplifying each term.
x=-y+35_y=7

Replace all occurrences of y with the solution found by solving the last equation for y.  In this case, the value substituted is 7.
x=-(7)+35_y=7

Multiply -1 by the 7 inside the parentheses.
x=-7+35_y=7

Add 35 to -7 to get 28.
x=28_y=7

This is the solution to the system of equations.
x=28_y=7




x+y=43_x=5+y

Since y does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting y from both sides.
x=-y+43_x=y+5

Replace all occurrences of x with the solution found by solving the last equation for x.  In this case, the value substituted is -y+43.
x=-y+43_(-y+43)=y+5

Remove the parentheses around the expression -y+43.
x=-y+43_-y+43=y+5

Since y contains the variable to solve for, move it to the left-hand side of the equation by subtracting y from both sides.
x=-y+43_-y+43-y=5

Since -y and -y are like terms, subtract y from -y to get -2y.
x=-y+43_-2y+43=5

Since 43 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 43 from both sides.
x=-y+43_-2y=-43+5

Add 5 to -43 to get -38.
x=-y+43_-2y=-38

Divide each term in the equation by -2.
x=-y+43_-(2y)/(-2)=-(38)/(-2)

Simplify the left-hand side of the equation by canceling the common factors.
x=-y+43_y=-(38)/(-2)

Simplify the right-hand side of the equation by simplifying each term.
x=-y+43_y=19

Replace all occurrences of y with the solution found by solving the last equation for y.  In this case, the value substituted is 19.
x=-(19)+43_y=19

Multiply -1 by the 19 inside the parentheses.
x=-19+43_y=19

Add 43 to -19 to get 24.
x=24_y=19

This is the solution to the system of equations.
x=24_y=19




y=5x_y=2x+3

Replace all occurrences of y with the solution found by solving the last equation for y.  In this case, the value substituted is 5x.
y=5x_(5x)=2x+3

Remove the parentheses around the expression 5x.
y=5x_5x=2x+3

Since 2x contains the variable to solve for, move it to the left-hand side of the equation by subtracting 2x from both sides.
y=5x_5x-2x=3

Since 5x and -2x are like terms, add -2x to 5x to get 3x.
y=5x_3x=3

Divide each term in the equation by 3.
y=5x_(3x)/(3)=(3)/(3)

Simplify the left-hand side of the equation by canceling the common factors.
y=5x_x=(3)/(3)

Simplify the right-hand side of the equation by simplifying each term.
y=5x_x=1

Replace all occurrences of x with the solution found by solving the last equation for x.  In this case, the value substituted is 1.
y=5(1)_x=1

Multiply 5 by each term inside the parentheses.
y=5_x=1

This is the solution to the system of equations.
y=5_x=1





x+y=39_x=y+5

Since y does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting y from both sides.
x=-y+39_x=y+5

Replace all occurrences of x with the solution found by solving the last equation for x.  In this case, the value substituted is -y+39.
x=-y+39_(-y+39)=y+5

Remove the parentheses around the expression -y+39.
x=-y+39_-y+39=y+5

Since y contains the variable to solve for, move it to the left-hand side of the equation by subtracting y from both sides.
x=-y+39_-y+39-y=5

Since -y and -y are like terms, subtract y from -y to get -2y.
x=-y+39_-2y+39=5

Since 39 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 39 from both sides.
x=-y+39_-2y=-39+5

Add 5 to -39 to get -34.
x=-y+39_-2y=-34

Divide each term in the equation by -2.
x=-y+39_-(2y)/(-2)=-(34)/(-2)

Simplify the left-hand side of the equation by canceling the common factors.
x=-y+39_y=-(34)/(-2)

Simplify the right-hand side of the equation by simplifying each term.
x=-y+39_y=17

Replace all occurrences of y with the solution found by solving the last equation for y.  In this case, the value substituted is 17.
x=-(17)+39_y=17

Multiply -1 by the 17 inside the parentheses.
x=-17+39_y=17

Add 39 to -17 to get 22.
x=22_y=17

This is the solution to the system of equations.
x=22_y=17





x+y=328_x=y+12

Since y does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting y from both sides.
x=-y+328_x=y+12

Replace all occurrences of x with the solution found by solving the last equation for x.  In this case, the value substituted is -y+328.
x=-y+328_(-y+328)=y+12

Remove the parentheses around the expression -y+328.
x=-y+328_-y+328=y+12

Since y contains the variable to solve for, move it to the left-hand side of the equation by subtracting y from both sides.
x=-y+328_-y+328-y=12

Since -y and -y are like terms, subtract y from -y to get -2y.
x=-y+328_-2y+328=12

Since 328 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 328 from both sides.
x=-y+328_-2y=-328+12

Add 12 to -328 to get -316.
x=-y+328_-2y=-316

Divide each term in the equation by -2.
x=-y+328_-(2y)/(-2)=-(316)/(-2)

Simplify the left-hand side of the equation by canceling the common factors.
x=-y+328_y=-(316)/(-2)

Simplify the right-hand side of the equation by simplifying each term.
x=-y+328_y=158

Replace all occurrences of y with the solution found by solving the last equation for y.  In this case, the value substituted is 158.
x=-(158)+328_y=158

Multiply -1 by the 158 inside the parentheses.
x=-158+328_y=158

Add 328 to -158 to get 170.
x=170_y=158

This is the solution to the system of equations.
x=170_y=158