Question 392558
(x^(2)-64)/(8-x)

The binomial can be factored using the difference of squares formula, because both terms are perfect squares.  The difference of squares formula is a^(2)-b^(2)=(a-b)(a+b).
((x-8)(x+8))/(-x+8)

Factor the expression.
((-1)(-x+8)(x+8))/(-x+8)

Reduce the expression by canceling out the common factor of (x-8) from the numerator and denominator.
((-1)<X>(x-8)<x>(x+8))/(-x+8)

Reduce the expression by canceling out the common factor of (x-8) from the numerator and denominator.
(-1)(x+8)

Multiply each term in the first polynomial by each term in the second polynomial.
(-1*x-1*8)

Multiply -1 by each term in x+8 to get -x-8.
(-x-8)

Remove the parentheses around the expression -x-8.
-x-8