Question 392509
(3x)^-3y^4
___________
-x^2y^-6
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= [(3x)^-3/-x^2]*[-3y^4/y^-6]
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= [-1/(27x^5)]*[-3y^10]
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= [3y^10/(27x^5)]
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= [y^10/(9x^5)]
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Cheers,
Stan H.