Question 392243
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Hi
Note: The probability of x successes in n trials is: 
P = nCx* {{{p^x*q^(n-x)}}} where p and q are the probabilities of success and failure respectively. 
In this case p = .2 and q = .8
nCx = {{{n!/(x!(n-x!))}}}
P(winning at least 4 of 7 games) = 1-P(no wins) -P(1 win) - P(2 wins) - P(3wins)
P(no wins) = (.8)^7 = .2097
P(1 win) = 7(.2)^1*(.8)^6 = .3670
P(2 wins)=  21(.2)^2*(.8)^5 = .2753
P(3wins)= 35(.2)^3*(.8)^4 = .1147
P(winning at least four games) = 1 -.9667 = .0333