Question 392211

32x + 23y = 10,100
12x + 14y = 5400

substitute the varible. I selected equation 2 first to solve for y, but couldn't get y by itself. please help...

subtracted 12x from both sides of 12x + 14y = 5400 I got:
14y = 5400-12x....what is my next step?
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y = (2700-6x)/7
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Substitute to get:
32x + 23[2700-6x]/7 = 10100
32x + (62100-138x)/7 = 10100
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Multiply thru by 7 to get:
224x + 62100 - 138x = 7*10100
86x = 8600
x = 100
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Substitute to solve for "y":
y = (2700-6*100)/7
y = (2100)/7
y = 300
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Cheers,
Stan H.