Question 392210
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Hi
two consecutive integers 
Let x and (x+1) represent the integers
Question States: Write as we Read
 x(x+1) = 72    |Writing as we Read Sets Up this 'equation'
solving for x
 x^2 + x = 72
 x^2 + x -72 = 0
factoring 
(x+9)(x -8)= 0 Note:SUM of the inner product(9x) and the outer product(-8x) = x
(x+9)= 0   x = -9  Consecutive Integers -9,-8
(x -8)= 0  x = 8   Consecutive Integers  8,9
both sets satisfy the conditions that   x(x+1) = 72