Question 392158
{{{3650 = 2000(1+0.04/2)^(2t)}}}
<==> {{{1.825 = (1.02)^(2t)}}}
<==> {{{ln 1.825 = (2ln 1.02)t}}}
<==> {{{t = ln1.825/(2ln1.02) = 15.19}}} years. (To 2 decimal places)