Question 392136
Find the equation (in terms of x) of the line through the points (-5,-4) and (2,1). 

Sol'n:
 Solve for the slope first:
 m =(y2-y2)/(x2-x1) let P1(-5,-4) & P2(2,1).
  = (1+4)/(2+5)
 m = 5/7

using point-slope form:
 y-y1 = m(x-x1) @ P1(-5,-4)
 y+4 = 5/7(x+5)
 7(y+4)= 5(x+5)
 7y+28 = 5x+25
 5x-7y-3 = 0 ---answer