Question 42664
Okay, the function we are working with is
C(t) = 0.1 + 2.78e^(-0.37t)
The initial concentration is when t = 0, so
C(0) = 0.1 + 2.78e^0 = 2.88
After three hours, t = 3, so we have
C(3) = 0.1 + 2.78e^(-0.37*3) and we use our calculator to get
C(3) = .916 mpg