Question 392006

{{{3/4x>2}}}...both sides multiply by {{{4}}}

{{{4(3/4)x>2*4}}}



{{{cross(4)(3/cross(4))x> 8}}}

{{{3/x > 8}}}........both sides multiply by {{{x}}}


{{{3x/x > 8x}}}

{{{3cross(x)/cross(x) > 8x}}}

{{{3 > 8x}}}.......both sides divide  by {{{8}}}


{{{3/8 > 8x/8}}


{{{3/8 > x}}..or....{{{x< 3/8}}


{{{x}}} will go from (-{{{infinity}}} ,3/8 )