Question 391957
  <pre><font size = 3 color = "indigo"><b>
Hi
Note: the vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
Parabola: x^2 = 12y  OR {{{y = (1/12)x^2  = x^2/4p}}} where Pt(0,p) is the focus 
parabola with center at Pt(0,0) and Pt(0,3) is the focus
and the length of the latus rectum chord = 4p = 12
the area of the triangle formed joining (Pt(0,0) to the ends of its latus-rectum
A = (1/2)b*h = 1/2 * 12 * 3 = 18
{{{drawing(300,300, -10,10,-10,10, grid(1),
circle(0, 3,0.3),
circle(6, 3,0.3),
circle(-6, 3,0.3),
blue(line (-6,3,6,3)),
line(0,0,6,3),
line(0,0,-6,3),
graph( 300, 300, -10,10,-10,10,0,(1/12)x^2))}}}