Question 391869
First of all, the quadratic equation is: {{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}
The function 7x^2-3x-2 is in the form {{{ax^2+bx+c}}}
Therefore,
{{{a=7}}}
{{{b=-3}}}
{{{c=-2}}}
Now you can simply plug in the variables.
{{{x=(-(-3)+sqrt((-3)^2-4(7)(-2))/(2(7)))}}}
and
{{{x=(-(-3)-sqrt((-3)^2-4(7)(-2))/(2(7)))}}}
The answers end up being:
{{{x=(3+sqrt(65))/14)}}}
and
{{{x=(3-sqrt(65))/14)}}}

Hope this help,
J