Question 391768
  <pre><font size = 3 color = "indigo"><b>
Hi,
  finding the intercepts for the line
y = 4x + 12   |crosses x-axis when y = 0
0 = 4x + 12
-12 = 4x
 -3 = x   x-intercept is Pt(-3,0)

y = 4x + 12     |crosses y-axis when x = 0
y = 4*0 + 12
y = 12    y-intercept is Pt(0,12)
Graph of y = 4x +12.  Note where the line crosses the x-axis and y-axis
{{{drawing(300,300,-20,20,-20,20, grid(1),
circle(0, 12,0.8),
circle(-3, 0,0.8),
graph( 300, 300, -20,20,-20,20,4x+12))}}}