Question 391719

{{{f(x) = 3x^3 - 2x^2 + x - 2 }}}........ {{{-2x^2}}} we can write as {{{-3x^2 +x^2}}}, and  {{{x }}} as {{{2x-x }}}

{{{f(x) = 3x^3 -3x^2 +x^2 + 2x-x - 2 }}}...now group them

{{{f(x) = (3x^3 -3x^2 )+(x^2  - x)+ (2x - 2) }}}

{{{f(x) = 3x^2(x - 1)+x(x  - x)+ 2(x - 1)}}}

{{{f(x) = (x - 1)(3x^2+x+ 2)}}}


since you have 

c. {{{(x+1) (3x^2 + x + 2)}}}
d. {{{(x+1) (3x^2 + x + 2)}}}

which are same, I guess you made mistake by typing d. I think you d should be

d. {{{(x-1) (3x^2 + x + 2)}}}