Question 390264
{{{f(x)=(x^2+x-6)/(x^2+2x-8) = ((x+3)(x-2))/((x+4)(x-2))}}}

Domain = R\{-4, 2}.  Then {{{f(x)= (x+3)/(x+4)}}}.

There is a "hole" in the graph at the point (2, 5/6).
Vertical asymptote: x = -4,
Horizontal asymptote: y = 1,
x-intercept:  -3,
y-intercept: 3/4.