Question 391673
What is the elimination method 2r-5s=-29 and 5r+2s=58?
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2r-5s=-29........................1 
5r+2s=58.........................2
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multiply (1)by 5 & (2) by -2
10r-25s=-145
-10r-4s=-116
Add them up
-25s-4s=-145-116
-29s==-261
/-29
{{{highlight(s= 9))}}}
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plug value of s in (1)
2r-5*9=-29
2r-45=-29
2r=45-29
2r=16
/2
{{{highlight(r=8))}}}
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