Question 391491
{{{a^(-n)*b^0}}}
Any number, except zero, raised to the zero power is always a 1. So as long as "b" in not zero, then {{{b^0 = 1}}} and the expression becomes:
{{{a^(-n)*1}}}
which simplifies to:
{{{a^(-n)}}}
And since {{{a^(-n)}}} means the reciprocal of {{{a^n}}}, this expression can be rewritten as:
{{{1/a^n}}}