Question 391535
a rectangle has a length that is three times its width. the diagonal of the rectangle is 50cm. find the width of the rectangle
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width = x
length = 3x
diagonal D = 50
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By Pythagoras theorem
D^2= x^2+(3x)^2
D^2=x^2+9x^2
D^2=10x^2
50^2= 10x^2
2500/10= x^2
250 = x^2
x= 15.8 cm the width
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