Question 391504
Hi, Here is the question. The base of a triangle is 4 cm greater than the height. The area is 30cm^2, find the height and length. 
I have done this so far,
A= (1/2)bh = 30
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(1/2)(x+4)x = 30
x^2+4x = 60
x^2+4x-60 = 0
x^2+10x-6x-60 = 0
x(x+10)-6(x+10) = 0
(x+10)(x-6) = 0
Positive solution:
x = 6cm(height)
x+4= 10cm(base)
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Cheers,
Stan H.
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