Question 391331
  <pre><font size = 3 color = "indigo"><b>
Hi,         
Using the vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
vertex of parabola is Pt(2,-9)
 y = a(x-2)^2 - 9    |Using x-intercept Pt(5,0) to solve for a
 0 = a*3^2 - 9
 9 = 9a
 a = 1
Graphing  y = (x-2)^2 - 9 
{{{drawing(300,300, -10, 10, -10, 10,blue(line(2,10,2,-10)), grid(1),
circle(2, -9,0.3),
circle(5, 0,0.3),
graph( 300, 300,  -10, 10, -10, 10,(x-2)^2 - 9  ))}}}