Question 391277

{{{log(x+2)+log x= 3 log 2}}}

{{{log(x(x+2))= log 2^3}}}

{{{x(x+2) = 2^3}}}

{{{x^2+2x = 8}}}

{{{x^2+2x-8 = 0}}}

{{{(x+4)(x-2) = 0}}}

x = {-4, 2}

Checking for extraneous solutions, we have to throw out the negative solution leaving:

x = 2