Question 389874
{{{sqrt(3x+1)+1=x}}},
==> {{{sqrt(3x+1) = x - 1}}},
==> {{{3x+1 = x^2 - 2x + 1}}},after squaring both sides.
==> {{{0 = x^2 - 5x}}}, or x(x - 5) = 0.
==> x = 0 or x = 5.  The 1st x-value will not satisfy the original equation, and the 2nd x-value does.  Therefore final answer is x = 5.