Question 391149
substituting ___ (x^2 / 4) + (x + 1)^2 = 1


x^2 + 4x^2 + 8x + 4 = 4


5x^2 + 8x = 0 ___ x(5x + 8) = 0 ___ x = 0 and x = -8/5


y = (0) + 1 = 1


y = (-8/5) + 1 = -3/5


the solution points are ___ (0,1) and (-8/5,-3/5)