Question 391152
Add the first two equations (this clears out the y-term) to get


4x + 2z = 20 --> 2x + z = 10


Multiply the second equation by 2, so we can add the second and third equations and also clear the y-terms. This results in another equation in terms of x and z that is not equivalent to the one we already obtained.


4x - 2y + 6z = 26
3x + 2y - z = 17
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7x + 5z = 43


We can rewrite this as 5(2x + z) - 3x = 43 --> 5(10) - 3x = 43 --> x = 7/3, z = 16/3. Substituting x and z into any of the equations, we get y = 23/3. Therefore the solution (x,y,z) is (7/3, 23/3, 16/3).