Question 42657
{{{h = -16t^2 + 48t}}} where {{{h}}} is height
{{{0 = -16t^2 + 48t}}} where the height from the ground is zero feet
Use Quadratic Formula:
{{{h = at^2 + bt + c}}}
{{{a = -16}}}
{{{b = 48}}}
{{{c = 0}}}
{{{t = (-b +- sqrt( b^2 - 4*a*c ))/(2*a) }}}
{{{t = (-48 +- sqrt( 48^2 - 4*(-16)*(0) ))/(2*(-16)) }}}
{{{t = (-48 +- sqrt( 48^2 ))/(-32)) }}}
{{{t = (-48 +- 48)/(-32)) }}}
{{{t = (-48 + 48)/(-32)}}} or {{{x = (-48 - 48)/(-32)}}}
{{{t = 0}}} or {{{x = 3}}}
{{{ graph( 600, 600, -10, 10, -10, 38, -16x^2 + 48x) }}}