Question 391110
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Presuming they are 4 distinctly different objects, then there are 4 ways to pick the first object.  For each of those 4 ways to pick the first object there are 3 ways to pick the second object, making a total of 12 ways to pick the first two objects, and so on times 2 then times 1.


Shorthand is 4! = 4 X 3 X 2 X 1


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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