Question 42645
Let n= First Integer
Let n+1= Second Integer

{{{2n+4(n+1)=46}}}
{{{2n+4n+4=46}}}
{{{6n+4=46}}}
{{{  -4=-4}}}
{{{6n=42}}}
{{{6n/6=42/6}}}
  n=7

Now we plug 7 into the n statements,
so the first number is 7 and the second is 8.