Question 390847
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(x)\ =\ -x^3\ -\ x^2\ +\ 2x\ + 6]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(-2)\ =\ -(-2)^3\ -\ (-2)^2\ +\ 2(-2)\ + 6]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(0)\ =\ -(0)^3\ -\ (0)^2\ +\ 2(0)\ + 6]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(3)\ =\ -(3)^3\ -\ (3)^2\ +\ 2(3)\ + 6]


You can do your own arithmetic.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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