Question 390812
Since the question is in the "logarithms" section, I'm more likely to interpret it as {{{4^((-3/4)x) = 1/2}}} or {{{4^(-3/4x) = 1/2}}}. The question is still ambiguous, but in either case, it can be solved by writing 1/2 as {{{4^(-1/2)}}}, then taking the log base 4 of both sides. It becomes a simple algebra problem there on.