Question 390638
Let x, x+2, x+4, x+6 be the 4 even integers.
[2x+5(x+2)+4(x+4)]/3(x+6)=3
[2x+5x+10+4x+16]/(3x+18)=3
[11x+26]/(3x+18)=3 cross multiply
11x+26=3(3x+18
11x+26=9x+54
11x-9x=54-26
2x=28
x=28/2
x=14 ans. for the first integer.
Proof:
[2*14+5(14+2)+4(14+4)]/3(14+6)=3
[28+5*16+4*18]/3*20=3
[28+80+72]/60=3
180/60=3
3=3