Question 390713
From {{{18x^2+10x+14}}} we can see that {{{a=18}}}, {{{b=10}}}, and {{{c=14}}}



{{{D=b^2-4ac}}} Start with the discriminant formula.



{{{D=(10)^2-4(18)(14)}}} Plug in {{{a=18}}}, {{{b=10}}}, and {{{c=14}}}



{{{D=100-4(18)(14)}}} Square {{{10}}} to get {{{100}}}



{{{D=100-1008}}} Multiply {{{4(18)(14)}}} to get {{{(72)(14)=1008}}}



{{{D=-908}}} Subtract {{{1008}}} from {{{100}}} to get {{{-908}}}



So the discriminant is {{{D=-908}}}



Since the discriminant is less than zero, this means that there are two complex solutions.



In other words, there are no real solutions.



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