Question 390652
log base 4 (x+3))+(log base 4 (x-3))=2
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log4(x+3) + log4(x-3) = 2
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log4[x^2-9] = 2
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base = 4
exponent = 2
result = x^2-9
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Write in exponential form:
x^2-9 = 4^2
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x^2 = 16+9
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x^2 = 25
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Positive solution:
x = 5
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Cheers,
Stan H.