Question 390606
<pre>
N+M is an odd number
M+T is an odd number 

Case 1:  If M is even, N and T are both odd 
         (in order to make both their sums with M odd).

Case 2:  If M is odd, N and T are both even 
         (in order to make both their sums with M even).

So N and T are the same type (parity) of integer, i.e., both odd or both even.

  a) NxT is even
This is false in case 1, since an odd times an odd is an odd

b) NxT is odd
This is false in case 2, since an even times an even is an even

c) N+T is odd
This is false in both cases, since if you add two odds or two evens, you get an even.

d) N+T is even
This is true in both cases, since if you add two odds or two evens, you get an even.

e) N-T is odd
This is false in both cases, since if you subtract two odds or two evens, you get an even.

So the only correct statement is d)

Edwin</pre>