Question 390614
<pre><font size = 3 color = "indigo"><b>
Hi, 
Note: setting = 0  so as it is an  'equation'      
{{{2x^2-3x+1 = 0}}}
factoring
(2x - 1)(x-1 = 0 Note:SUM of the inner product(-x) and the outer product(-2x) = -3x
 (2x - 1)= 0
      x = 1/2 crosses x axis at Pt(1/2,0)
 (x-1) = 0
      x = 1   crosses x axis at Pt(1,0)
{{{drawing(300,300, -6, 6, -6, 6, grid(1),
circle(1, 0,0.3),
circle(.5, 0,0.3),
graph( 300, 300, -6, 6, -6, 6,2x^2-3x+1))}}}