Question 390589
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Hi,         
Note: The probability of x successes in n trials is: 
P = nCx* {{{p^x*q^(n-x)}}} where p and q are the probabilities of success and failure respectively. 
In this case p= .95 & q = .05
 nCx = {{{n!/(x!(n-x!))}}}
P(working properly for 10 days in row) = .95^10 = .5987