Question 390553
 
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Hi

A={{{(matrix(3,3,a1,b1,c1,a2,b2,c2,a3,b3,c3))}}} ={{{(matrix(3,3,-4,3,2,1,-32,1,6,-2,-1))}}}
I. first find value of determinant: d =  a1(b2c3-c2b3) - b1(a2c3-c2a3) + c1(a2b3-b2a3) 
II. Then Apply formula for the Inverse: 
|A| = 1/d{{{matrix(3,3,(b2*c3-c2*b3),(c1*b3-b1*c3),(b1*c2-c1*b2),
                   (c2a3-a2c3),(a1c3-c1a3),(c1a2-a1c2),
                   (a2b3 - b2a3), (b1a3 -a1b3),(a1b2-b1a2)))}}}