Question 390510
The vertex form is, {{{y = a(x-h)^2 + k}}} where (h,k) is the vertex.
{{{h = -b/2a = 7/6}}},
{{{k = (4ac - b^2)/4a = (4*3*-20 - 49)/12 = -289/12}}}.
Therefore the vertex form is 
 {{{y = 3(x-7/6)^2 - 289/12}}}