Question 390460
2x+4y=56_x+y=17

Since y does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting y from both sides.
2x+4y=56_x=-y+17

Replace all occurrences of x with the solution found by solving the last equation for x.  In this case, the value substituted is -y+17.
2(-y+17)+4y=56_x=-y+17

Multiply 2 by each term inside the parentheses.
-2y+34+4y=56_x=-y+17

Since -2y and 4y are like terms, subtract 4y from -2y to get 2y.
2y+34=56_x=-y+17

Since 34 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 34 from both sides.
2y=-34+56_x=-y+17

Add 56 to -34 to get 22.
2y=22_x=-y+17

Divide each term in the equation by 2.
(2y)/(2)=(22)/(2)_x=-y+17

Simplify the left-hand side of the equation by canceling the common factors.
y=(22)/(2)_x=-y+17

Simplify the right-hand side of the equation by simplifying each term.
y=11_x=-y+17

Replace all occurrences of y with the solution found by solving the last equation for y.  In this case, the value substituted is 11.
y=11_x=-(11)+17

Multiply -1 by the 11 inside the parentheses.
y=11_x=-11+17

Add 17 to -11 to get 6.
y=11_x=6

This is the solution to the system of equations.
y=11_x=6